循环结构(break结束) |
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print("韩信点兵求人数:") print("规则:三三数之剩二,五五数之剩四,七七数之剩六") n = 1000 while True: if n % 3 == 2 and n % 5 == 4 and n % 7 == 6: break else: n += 1 print("士兵有:{}人。".format(n)) |
2021-10-29 |
time库 |
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2021-10-13 |
建立身份证号码验证函数,并批量验证身份证号码 |
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2021-10-12 |
验证身份证号码是否正确 |
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2021-10-11 |
身份证信息识别 |
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2021-10-10 |
切片 |
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s1 = "I am Chinese" print(s1[2:4]) |
2021-10-09 |
pow()函数 |
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for i in range(100,1000): if pow(i //100 ,3) +pow(i %10 ,3) +pow( |
2021-10-09 |
0000-00-00 |
test |
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0000-00-00 |