Python每日一题

循环结构(break结束)
print("韩信点兵求人数:")
print("规则:三三数之剩二,五五数之剩四,七七数之剩六")
n = 1000
while True:
    if n % 3 == 2 and n % 5 == 4 and n % 7 == 6:
        break
    else:
        n += 1
print("士兵有:{}人。".format(n))
2021-10-29
time库
2021-10-13
建立身份证号码验证函数,并批量验证身份证号码
2021-10-12
验证身份证号码是否正确
2021-10-11
身份证信息识别
2021-10-10
切片
s1 = "I am Chinese"
print(s1[2:4])
2021-10-09
pow()函数
for i in range(100,1000):
    if pow(i //100 ,3) +pow(i %10 ,3) +pow(
i //10 %10,3) == i: print(i,end=" ")
2021-10-09
0000-00-00
test
0000-00-00